I’ve been playing Progate lightly and have no Java experience, so I am solving the paiza skill check problem in the training, but I made a note because I was stuck unexpectedly on the first day.
As soon as you start the skill check
Input the letter N, so output N
You will be instructed what to do.
It ends with outputting with System.out.print~! I think It is a mistake to write it as it is.
Unlike Progate which is followed variously It is necessary to read the value entered in the skill check here. If you don’t know how to read the input value, paiza cannot even get D rank.
In the case of a problem like the one at the beginning, because it is a character
// define a variable Scanner sc = new Scanner(System.in); // get the string String t = sc.nextLine();
If you read it in with this, you can output it.
When numbers are entered
The numbers are almost the same.
// get the number int t = sc.nextInt();
Please note that it is “nextInt”.
read one by one
For example, suppose a letter is given in the form of one line N B and needs to be N + B.
In this case, if you use nextLine();, N and B will be read together. It seems good to use next();.
// read N String x = sc.next(); // load B String y = sc.next();
next() reads up to half-width space, so pseudo splitting is possible without using split. You can use the same with numbers. *However, since it is read as “character”, it is necessary to specify the type of String.
read multiple lines
Suppose the number 1 is given on the first line and the letter N is given on the second line.
In this case, it seems to be better to get each with nextInt();,nextLine(); Writing this way will result in an error.
// error example int t = sc.nextInt(); String a = sc.nextLine();
Because nextInt() reads an integer, the newline character actually remains. With this process, the second line cannot be read. So you need to add nextLine(); and skip it.
// read the integer on the first line int t = sc.nextInt(); // skip newline characters sc.nextLine(); // read the character on the second line String a = sc.nextLine();
Paiza has quite a few problems of this type, so it’s worth remembering. I didn’t know why I wasn’t working, so I was pretty busy.
You can also get it as a List, but if you can get the values and characters properly Now you can concentrate on processing the logic. It’s important to visualize what nextLine();, next(); and nextInt(); are doing.
It’s a simple story for anyone I know. Probably because I was learning based on Progate and books, I stumbled on the unexpected part, so I hope it will be helpful. According to my senior, it seems that it is not used much in the actual field, but it is an important knowledge to capture paiza’s skill check.