# [RUBY] How to output the sum of any three numbers, excluding the same value

## 【Overview】

1. Conclusion </ b>

2. How to code </ b>

1. Conclusion

Use arrays, each methods, if statements </ b>!

## 2. How to code

``````def any_three_sum(array)
unique_nums = [] #---❶
array.each do |num| #---❷
count = 0
array.each do |i| #---❸
if num == i
count += 1
end
end
if count < 2 #---❹
unique_nums << num
end
end

three_sum = 0 #---❺
unique_nums.each do |unique_num|
three_sum += unique_num
end

puts three_sum

end
``````

First of all, I am coding a program that retrieves numbers that are not covered. For example, consider any_three_sum ([4,3,4]). ❶: We have prepared a box to put unique numbers in the array. Use it again in ❺. ❷: num = 4, num = 3, num = 4, and each is taken out. ❸: If the number taken out in ❷ and the number in ❸i = [4,3,4] are the same, count is set to +1. I am doing important coding when duplicating ❹. ❹: When count <2, it is included in the array in unique_nums. Since count counts duplicate numbers, if num = 4, count = 2, so it is not added to unique_sums. So num = 3 is added to unique_sums. ❺: Since only unique_sums = [3], puts three_sum will be “3”. The values of unique_sums are taken out (= each) and all are summed (the first and second numbers are also reflected by three_sum + =) and assigned to the three_sum variable.