What I've been working on right now It was to enter a positive integer and output True if it was less than or equal to a multiple of 10 and False otherwise.
Below is my answer.
def near_ten(num)
basis = (num + 5) / 10 * 10
difference = (num - basis).abs
if difference <= 2
puts "True"
else
puts "False"
end
end
First, let basis be the multiple of 10 that is closest to num.
The second line calculates the numbers suitable for basis.
basis = (num + 5) / 10 * 10
As an example, if it is an integer from 15 to 24, the nearest multiple of 10 is 20, so I want to use 20 as a reference.
Add 5 to each of these integers to get 20-29.
These integers have 2 in the tens place, so if you do / 10 * 10 respectively, 20 will come out, which is the number you want to use as a reference.
Other integers work just as well.
This completes the basis part.
Next, the difference between the original number and this standard is calculated.
num - basis
Since the difference may be negative as it is, we use a method that gives an absolute value.
(num - basis).abs
Then substitute this
difference = (num - basis).abs
If the difference difference obtained in this way is 2 or less, it is sufficient, so it is judged and the process ends.
if difference <= 2
puts "True"
else
puts "False"
end
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