[JAVA] [Head panic] Priority when variables / methods with the same name are used in inherited classes

A.java

public class A {
	String val = "A";
	void print() {
		System.out.println(val);
	}
}

B.java

public class B extends A {
	String val = "B";

    @Override
	void print() {
		System.out.println(val);
	}
}

Implement & execute the following using these classes

Main.java

public class Main {
	public static void main(String[] args) {
		A a = new A();
		 //Since B class inherits from A class, A can be used as the type of variable.
		A b = new B(); 
		
		//Since the type of b is A, val uses the value of the field defined in type A
		System.out.println("Show a val: " + a.val); // A
		System.out.println("Show val of b: " + b.val); // A
		
        System.out.print("print of a()Execute method: "); 
		a.print(); // A
		System.out.print("b print()Execute method: ");
		b.print();// B
     }
}

When displaying b.val, "A" is displayed Because we are using A as the type of variable b and the field of A is used.

On the other hand, "B" is displayed in b.print () This is because the print () method is overridden in the B class, and the B class method takes precedence when new B () is executed.

Note that the method is overridden, but the behavior changes because the variable is tied to the field.