Vous pouvez utiliser include () pour extraire le paramètre PATH, mais que faites-vous réellement?
(référence) mysite/urls.py
from django.contrib import admin
from django.urls import include, path
urlpatterns = [
path('polls/', include('polls.urls')),
path('admin/', admin.site.urls),
]
Texte original dans la fonction réelle
def include(arg, namespace=None):
app_name = None
if isinstance(arg, tuple):
# Callable returning a namespace hint.
try:
urlconf_module, app_name = arg
except ValueError:
if namespace:
raise ImproperlyConfigured(
'Cannot override the namespace for a dynamic module that '
'provides a namespace.'
)
raise ImproperlyConfigured(
'Passing a %d-tuple to include() is not supported. Pass a '
'2-tuple containing the list of patterns and app_name, and '
'provide the namespace argument to include() instead.' % len(arg)
)
else:
# No namespace hint - use manually provided namespace.
urlconf_module = arg
if isinstance(urlconf_module, str):
urlconf_module = import_module(urlconf_module)
patterns = getattr(urlconf_module, 'urlpatterns', urlconf_module)
app_name = getattr(urlconf_module, 'app_name', app_name)
if namespace and not app_name:
raise ImproperlyConfigured(
'Specifying a namespace in include() without providing an app_name '
'is not supported. Set the app_name attribute in the included '
'module, or pass a 2-tuple containing the list of patterns and '
'app_name instead.',
)
namespace = namespace or app_name
# Make sure the patterns can be iterated through (without this, some
# testcases will break).
if isinstance(patterns, (list, tuple)):
for url_pattern in patterns:
pattern = getattr(url_pattern, 'pattern', None)
if isinstance(pattern, LocalePrefixPattern):
raise ImproperlyConfigured(
'Using i18n_patterns in an included URLconf is not allowed.'
)
return (urlconf_module, app_name, namespace)
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