Let's search from the procession

Good evening ('Д') Thank you for your support m (_ _) m

I've written various algorithms, I wanted to play in a line for a short break. I'll start with the easy guy.

test.py

import numpy as np
Tarray = np.arange(12)
print(Tarray)

Execution result.py

[ 0  1  2  3  4  5  6  7  8  9 10 11]

Can this be changed to, for example, 3 rows and 4 columns? Yes you can.

test.py

import numpy as np
Tarray = np.arange(12).reshape(3,4)
print(Tarray)

Execution result.py

[[ 0  1  2  3]
 [ 4  5  6  7]
 [ 8  9 10 11]]

I see, it's interesting !! From here, to print only specific elements What should i do? How about such a description? ..

test.py

import numpy as np

Tarray = np.arange(12).reshape(3,4)

print(Tarray)
print()
print(f"Tarray[0,0] is {Tarray[0,0]}")

Execution result.py

[[ 0  1  2  3]
 [ 4  5  6  7]
 [ 8  9 10 11]]

Tarray[0,0] is 0

I see. (´ ー ｀) y- ~~ Once you know this far You may be able to find the number you want from the procession. Let's do it (≧ ▽ ≦)

For example, data from the first row of 2 rows and 10 columns Wouldn't it be like this when extracting?

test.py

import numpy as np

Tarray = np.arange(20).reshape(2,10)
print(Tarray)
num = int(input(": "))

for i in range(10):
    if Tarray[0,i] == num:
        print(f"founded data is placed Tarray[0,{i}] ")

Execution result.py

[[ 0  1  2  3  4  5  6  7  8  9]
 [10 11 12 13 14 15 16 17 18 19]]

: 6
founded data is placed Tarray[0,6] 

Next, let's search across lines. It's OK if you change 0 in Tarray [0, i] above to a variable.

test.py

import numpy as np

Tarray = np.arange(20).reshape(2,10)
print(Tarray)
num = int(input(": "))

for j in range(2):
    for i in range(10):
        if Tarray[j,i] == num:
            print(f"founded data is placed Tarray[{j},{i}] ")

Execution result.py

[[ 0  1  2  3  4  5  6  7  8  9]
 [10 11 12 13 14 15 16 17 18 19]]

: 13
founded data is placed Tarray[1,3] 

But what if even rows and columns become variables? I wrote it like this.

matrix_search.py

import numpy as np

M,N = map(int,input("enter M , N: ").split())
atest = np.arange(M*N).reshape(M,N)
print(atest)

num = int(input("find value: "))

for i in range(M):
    for j in range(N):
        if atest[i,j] == num:
            print(f"found value is placed at　[{i},{j}]")

Execution result.py

enter M , N: 4 8
[[ 0  1  2  3  4  5  6  7]
 [ 8  9 10 11 12 13 14 15]
 [16 17 18 19 20 21 22 23]
 [24 25 26 27 28 29 30 31]]

find value: 20
found value is placed at [2,4]

The position display is configured as having 0 rows and 0 columns. There is no such thing (laugh)

matrix_search.py

import numpy as np

M,N = map(int,input("enter M , N: ").split())
atest = np.arange(M*N).reshape(M,N)
print(atest)

num = int(input("find value: "))

for i in range(M):
    for j in range(N):
        if atest[i,j] == num:
            print(f"found value is placed at　[{i+1},{j+1}]")

Execution result.py

enter M , N: 4 8
[[ 0  1  2  3  4  5  6  7]
 [ 8  9 10 11 12 13 14 15]
 [16 17 18 19 20 21 22 23]
 [24 25 26 27 28 29 30 31]]

find value: 20
found value is placed at [3,5]

Yes, this time it looks okay. See you again ^^) _ Dan ~~