[Ruby] A program that uses search and each_with_index

I am reviewing the drill to strengthen my logical thinking. As a beginner, I would appreciate it if you could let me know if you have any questions. This time is my failure story.

problem

From the following array, create a search method using each_with_index that searches for a number and returns the result of what number it is included in.

ruby.rb

input = [3, 5, 9 ,12, 15, 21, 29, 35, 42, 51, 62, 78, 81, 87, 92, 93]

Model answer

ruby.rb

def search(target_num, input)

  input.each_with_index do |num, index|
    if num == target_num
      puts "#{index + 1}Is in the second"
      return
    end
  end
  puts "That number is not included"
end

input = [3, 5, 9 ,12, 15, 21, 29, 35, 42, 51, 62, 78, 81, 87, 92, 93]
search(11, input)

#result
That number is not included

My mistake answer

ruby.rb

def search(target_num, input)

  input.each_with_index do |num, index|
     if num == target_num
        puts "#{num}Is#{index + 1}It is in the second."
     else
        puts "#{num}Is not included."
     end
   end
end

input = [3, 5, 9 ,12, 15, 21, 29, 35, 42, 51, 62, 78, 81, 87, 92, 93]
search(12, input)


#result
3 is not included.
5 is not included.
9 is not included.
12 is in fourth place.
15 is not included.
21 is not included.
29 is not included.
35 is not included.
42 is not included.
51 is not included.
62 is not included.
78 is not included.
81 is not included.
87 is not included.
92 is not included.
93 is not included.

Reflection

The processing result has been output for all the elements of the input array passed as an argument. Furthermore, since else is used for conditional branching, if they do not match, even if they exist in the array, they will be displayed as "not included".

Therefore, the following two points are required. ① Eliminate else ② Stop with return

(1) Since each_with_index is an iterative process, it will check each value in the input array. Therefore, if else is placed, each result will also be displayed, so only if.

ruby.rb

input.each_with_index do |num, index|

 if num == target_num
      puts "#{index + 1}Is in the second"
 end
end

And when all the values ​​in each_with_index's array have been checked, As a result, I want you to return "not included", so put puts outside the conditional branch + iterative processing.

ruby.rb

def search(target_num, input)

  input.each_with_index do |num, index|
    if num == target_num
      puts "#{index + 1}Is in the second"
    end
  end
  puts "That number is not included"
end

(2) Even if the existence of the desired numerical value can be confirmed, "the number is not included" will be displayed if it is left as it is. It looks like the following.

ruby.rb

def search(target_num, input)

  input.each_with_index do |num, index|
    if num == target_num
      puts "#{index + 1}Is in the second"
    end
  end
  puts "That number is not included"
end

input = [3, 5, 9 ,12, 15, 21, 29, 35, 42, 51, 62, 78, 81, 87, 92, 93]
search(12, input)


#result
4th
That number is not included

If you can confirm the existence of the value, you want to end the method at that point, so put a return after displaying "It is in the ◯ th".