Call bash with golang

Wait until execution is completed without receiving command result

• Run

package main

import (
    "fmt"
    "os/exec"
)

func main() {
    err := exec.Command("pwd").Run()
    if err != nil {
        fmt.Println("Command Exec Error.")
    }
}

Receive command results

• Output

package main

import (
	"fmt"
	"os/exec"
)

func main() {
	out, err := exec.Command("pwd").Output()
	if err != nil {
		fmt.Println("Command Exec Error.")
	}

	//Output the result of the executed command
	fmt.Printf("pwd result: %s", string(out))
}

Receive standard output error

- CombinedOutput

package main

import (
	"fmt"
	"os/exec"
)

func main() {
	out, err := exec.Command("ls", "dummy").CombinedOutput()
	if err != nil {
		fmt.Println("Command Exec Error.")
	}

	//Contents of standard output + standard error output of the executed command
	fmt.Printf("ls result: \n%s", string(out))
}

Do not wait for command execution to finish

• start --You can wait in combination with wait

package main

import (
	"fmt"
	"os/exec"
)

func main() {
	cmd := exec.Command("sleep", "10")

	fmt.Println("Command Start.")

	err := cmd.Start()
	if err != nil {
		fmt.Println("Command Exec Error.")
	}

	//Wait when uncommented
	//cmd.Wait()

	fmt.Println("Command Exit.")
}

reference

https://blog.y-yuki.net/entry/2017/04/28/000000