Find out how many each character is in the string.

s = 'aeqwtwegwa'
d = {}

for c in s:
    if c not in d:
        d[c] = 0
    d[c] += 1

print(d)

{'a': 2, 'e': 2, 'q': 1, 'w': 3, 't': 1, 'g': 1}

s = 'aefqwdqfqwe'
d = {}

for c in s:
    d.setdefault(c, 0)
    d[c] += 1

print(d)

{'a': 1, 'e': 2, 'f': 2, 'q': 3, 'w': 2, 'd': 1}

from collections import defaultdict

s = 'raegiowejgohg'
d = defaultdict(int)

for c in s:
    d[c] += 1
    
print(d)
print(d['g'])

defaultdict(<class 'int'>, {'r': 1, 'a': 1, 'e': 2, 'g': 3, 'i': 1, 'o': 2, 'w': 1, 'j': 1, 'h': 1})
3

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