AtCoder ABC177

Summary

AC is only A problem. Immediately after the end, I was able to AC the B problem.

A - Don't be late I wrote it according to the problem. I remember the math class.

D,T,S = map(int,input().split())
if D / S <= T:
    print("Yes")
else:
    print("No")

B - Substring I was able to AC immediately after the end.

S = input()
T = input()
sl = len(S)
tl = len(T)
ans = tl
for i in range(sl - tl + 1):
    flag = 0
    tmp = 0
    for j in range(tl):
        if S[j + i] == T[j]:
            tmp += 1
    ans = min(ans,tl - tmp)

print(ans)

C - Sum of product of pairs I was able to AC by referring to the cumulative sum of the explanations.

N = int(input())
A = list(map(int,input().split()))
s = [0]
for i in range(N):
    s.append(s[i] + A[i])
ans = 0
for i in range(N):
    ans += A[i] * (s[N] - s[i + 1])
print(ans % (10 ** 9 + 7))

Finally

This time it was not good. Solve past questions and practice.

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