abc155 participation report

A

The mounting was sober and annoying. It seems easy to implement if you listen to the explanation and remove the counterexample. I used Counter.

from collections import Counter
a = Counter(map(int,input().split()))
if 2 in a.values():
    print("Yes")
else:
    print("No")

B Implementation is not so difficult due to the upper limit of the number of inputs. I want to be able to combine if statements into one.

N = int(input())
A = list(map(int,input().split()))
for a in A:
    if a % 2 == 1:
        continue
    if a % 3 != 0 and a % 5 != 0:
        print("DENIED")
        exit()
print("APPROVED")

C Save the most frequent occurrences in a variable. After that, only the sorted character strings that match the maximum number of times are displayed.


from collections import Counter
N = int(input())
S = Counter(input() for _ in range(N))
S = S.most_common()
most_count = S[0][1]
S.sort()
for i in range(len(S)):
    if S[i][1] == most_count:
        print(S[i][0])

D I had a bad feeling when I saw the problem statement, so I went to the standings. Most people prioritized E over D, so skip

E I skipped D, but I couldn't implement it. This is not good.

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