AtCoder Beginner Contest 176 Participation Report

AtCoder Beginner Contest 176 Participation Report

ABC176A - Takoyaki

Break through in 2 minutes. Just write.

N, X, T = map(int, input().split())

print((N + X - 1) // X * T)

ABC176B - Multiple of 9

Break through in one and a half minutes. Just write.

N = input()

if sum(int(c) for c in N) % 9 == 0:
    print('Yes')
else:
    print('No')

It seems that the following was also good in Python. I wonder.

N = int(input())

if N % 9 == 0:
    print('Yes')
else:
    print('No')

ABC176C - Step

Break through in about 3 minutes. If the previous person is higher, just repeat adding on the table to the same height as the previous person.

N, *A = map(int, open(0).read().split())

result = 0
p = A[0]
for i in range(1, N):
    if p >= A[i]:
        result += p - A[i]
    else:
        p = A[i]
print(result)

ABC176D - Wizard in Maze

Break through in 81 minutes, TLE × 2. I was careful that if I implemented it poorly, I would go to the place where I could go with one warp in two times. If there is only one queue, * O * (* HW) in the warp process Since it would be necessary to scan *), if I made two queues and tried to warp only from the cells visited by BFS, the amount of calculation that can be AC was achieved.

package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
)

func min(x, y int) int {
	if x < y {
		return x
	}
	return y
}

func max(x, y int) int {
	if x > y {
		return x
	}
	return y
}

func main() {
	defer flush()

	H := readInt()
	W := readInt()
	Ch := readInt() - 1
	Cw := readInt() - 1
	Dh := readInt() - 1
	Dw := readInt() - 1
	S := make([]string, H)
	for i := 0; i < H; i++ {
		S[i] = readString()
	}

	t := make([][]int, H)
	for i := 0; i < H; i++ {
		t[i] = make([]int, W)
		for j := 0; j < W; j++ {
			if S[i][j] == '#' {
				t[i][j] = -1
			} else {
				t[i][j] = math.MaxInt64
			}
		}
	}

	warpCount := 0
	t[Ch][Cw] = warpCount
	q := make([][2]int, 0, 1024)
	q = append(q, [2]int{Ch, Cw})

	warpq := make([][2]int, 0, 1024)
	for len(q) != 0 {
		for len(q) != 0 {
			warpq = append(warpq, q[0])
			h, w := q[0][0], q[0][1]
			q = q[1:]
			if h-1 >= 0 && t[h-1][w] > warpCount {
				q = append(q, [2]int{h - 1, w})
				t[h-1][w] = t[h][w]
			}
			if h+1 < H && t[h+1][w] > warpCount {
				q = append(q, [2]int{h + 1, w})
				t[h+1][w] = t[h][w]
			}
			if w-1 >= 0 && t[h][w-1] > warpCount {
				q = append(q, [2]int{h, w - 1})
				t[h][w-1] = t[h][w]
			}
			if w+1 < W && t[h][w+1] > warpCount {
				q = append(q, [2]int{h, w + 1})
				t[h][w+1] = t[h][w]
			}
		}

		if t[Dh][Dw] != math.MaxInt64 {
			break
		}

		warpCount++
		for i := 0; i < len(warpq); i++ {
			h, w := warpq[i][0], warpq[i][1]
			for i := max(0, h-2); i <= min(H-1, h+2); i++ {
				for j := max(0, w-2); j <= min(W-1, w+2); j++ {
					if t[i][j] <= warpCount {
						continue
					}
					t[i][j] = warpCount
					q = append(q, [2]int{i, j})
				}
			}
		}
		warpq = warpq[:0]
	}

	if t[Dh][Dw] == math.MaxInt64 {
		println(-1)
	} else {
		println(t[Dh][Dw])
	}
}

const (
	ioBufferSize = 1 * 1024 * 1024 // 1 MB
)

var stdinScanner = func() *bufio.Scanner {
	result := bufio.NewScanner(os.Stdin)
	result.Buffer(make([]byte, ioBufferSize), ioBufferSize)
	result.Split(bufio.ScanWords)
	return result
}()

func readString() string {
	stdinScanner.Scan()
	return stdinScanner.Text()
}

func readInt() int {
	result, err := strconv.Atoi(readString())
	if err != nil {
		panic(err)
	}
	return result
}

var stdoutWriter = bufio.NewWriter(os.Stdout)

func flush() {
	stdoutWriter.Flush()
}

func println(args ...interface{}) (int, error) {
	return fmt.Fprintln(stdoutWriter, args...)
}

I ended up tuned crisply, but I managed to get it through Python.

from collections import deque


def main():
    from sys import stdin
    readline = stdin.readline

    from builtins import max, min, range

    INF = 10 ** 6

    H, W = map(int, readline().split())
    Ch, Cw = map(lambda x: int(x) - 1, readline().split())
    Dh, Dw = map(lambda x: int(x) - 1, readline().split())
    S = [readline()[:-1] for _ in range(H)]

    t = [[INF] * W for _ in range(H)]
    for h in range(H):
        th = t[h]
        Sh = S[h]
        for w in range(W):
            if Sh[w] == '#':
                th[w] = -1

    t[Ch][Cw] = 0
    q = deque([(Ch, Cw)])
    warp_count = 0
    warpq = []
    while q:
        while q:
            warpq.append(q[0])
            h, w = q.popleft()
            if h - 1 >= 0 and t[h - 1][w] > warp_count:
                q.append((h - 1, w))
                t[h - 1][w] = warp_count
            if h + 1 < H and t[h + 1][w] > warp_count:
                q.append((h + 1, w))
                t[h + 1][w] = warp_count
            if w - 1 >= 0 and t[h][w - 1] > warp_count:
                q.append((h, w - 1))
                t[h][w - 1] = warp_count
            if w + 1 < W and t[h][w + 1] > warp_count:
                q.append((h, w + 1))
                t[h][w + 1] = warp_count

        if t[Dh][Dw] != INF:
            break

        warp_count += 1
        for h, w in warpq:
            for i in range(max(0, h - 2), min(H, h + 3)):
                ti = t[i]
                for j in range(max(0, w - 2), min(W, w + 3)):
                    if ti[j] > warp_count:
                        ti[j] = warp_count
                        q.append((i, j))
        warpq.clear()

    if t[Dh][Dw] == INF:
        print(-1)
    else:
        print(t[Dh][Dw])


main()

ABC176E - Bomber

I couldn't break through. If I could solve the D problem 10 minutes earlier ... Or rather, if I skipped D and touched this one ...

Addendum: Obviously this is easier than the D problem. Select the vertical and horizontal with the most blast targets (note that there may be multiple candidates). Double count if there is a blast target at the bomb installation position It is necessary to subtract 1 because it becomes. If you try to remember whether there is a bomb target at the bomb installation position with a simple two-dimensional array, 6 × 10 10 </ sup> bits = 7.5 GB storage capacity is required Therefore, it is memorized by the tuple set of the position.

H, W, M = map(int, input().split())

rows = [0] * H
cols = [0] * W
s = set()
for _ in range(M):
    h, w = map(lambda x: int(x) - 1,input().split())
    rows[h] += 1
    cols[w] += 1
    s.add((h, w))

max_rows = max(rows)
max_cols = max(cols)

max_rows_indexes = [i for i in range(H) if rows[i] == max_rows]
max_cols_indexes = [i for i in range(W) if cols[i] == max_cols]

duplicate = True
if M >= len(max_rows_indexes) * len(max_cols_indexes):
    for h in max_rows_indexes:
        for w in max_cols_indexes:
            if (h, w) not in s:
                duplicate = False
                break
        if not duplicate:
            break
else:
    duplicate = False

if duplicate:
    print(max_rows + max_cols - 1)
else:
    print(max_rows + max_cols)

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