AtCoder Beginner Contest 163 Participation Report

AtCoder Beginner Contest 163 Participation Report

Recently, I was a regular in the top 20%, but this time it was in the top 38.4%, so it was good to be unrated ....

ABC163A - Circle Pond

It broke through in 4 minutes. I only wrote it, but it took me a long time because I couldn't see the problem sentence for more than 2 minutes from the beginning. You remember the formula of the length of the circumference, right?

from math import pi

R = int(input())

print(2 * pi * R)

ABC163B - Homework

Break through in one and a half minutes. Just write. Simply add up the number of days required for your homework and compare it with the number of days during the summer vacation.

N, M = map(int, input().split())
A = list(map(int, input().split()))

a = sum(A)

if a > N:
    print(-1)
else:
    print(N - a)

Postscript: This is good.

N, M = map(int, input().split())
A = list(map(int, input().split()))

print(max(N - sum(A), -1))

ABC163C - management

It broke through in 7 and a half minutes. I made a list of direct subordinates in the dictionary, but now I realized that I'm doing too much in vain. It's easier to add the number of people to the list obediently ....

N = int(input())
A = list(map(int, input().split()))

d = {}

for i in range(N - 1):
    if A[i] in d:
        d[A[i]].append(i + 2)
    else:
        d[A[i]] = [i + 2]

for i in range(1, N + 1):
    if i in d:
        print(len(d[i]))
    else:
        print(0)

Postscript: This is good.

N = int(input())
A = list(map(int, input().split()))

result = [0] * N
for a in A:
    result[a - 1] += 1
print('\n'.join(map(str, result)))

ABC163D - Sum of Large Numbers

Rainy day defeat. 0 was too disturbing.

Postscript: Why did I worry about the combination calculation and 0 being a hindrance and duplication? It's really too stupid and I'm in trouble.

N, K = map(int, input().split())

result = 0
for i in range(K, N + 2):
    # max: N, N -1, ..., N - i + 1
    a = (N + (N - i + 1)) * i // 2
    # min: 0, 1, .., i - 1
    b = (0 + (i - 1)) * i // 2
    result += a - b + 1
    result %= 1000000007
print(result)

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