AtCoder Beginner Contest 150 Participation Report

AtCoder Beginner Contest 150 Participation Report

ABC150A - 500 Yen Coins

Break through in 5 minutes. Just write. It took a long time because the problem statement was not displayed in the middle.

K, X = map(int, input().split())

if 500 * K >= X:
    print('Yes')
else:
    print('No')

ABC150B - Count ABC

Break through in two and a half minutes. Just write.

N = int(input())
S = input()

result = 0
for i in range(N):
    if S[i:i+3] == 'ABC':
        result += 1
print(result)

ABC150C - Count Order

It broke through in 26 minutes. It was difficult for a C problem, or I didn't feel like I could solve it at first. I wish I had just added up honestly ...

N = int(input())
P = list(map(int, input().split()))
Q = list(map(int, input().split()))

fac = [0] * 8
fac[1] = 1
for i in range(2, N):
    fac[i] = i * fac[i - 1]

a = 0
l = list(range(1, N + 1))
for i in range(N):
    a += l.index(P[i]) * fac[len(l) - 1]
    l.remove(P[i])

b = 0
l = list(range(1, N + 1))
for i in range(N):
    b += l.index(Q[i]) * fac[len(l) - 1]
    l.remove(Q[i])

print(abs(a - b))

ABC150D - Semi Common Multiple

Defeated.

Postscript: I wrote it according to the explanation in PDF.

from fractions import gcd

N, M = map(int, input().split())
A = list(map(int, input().split()))

a = A[0]
n = 1
while a % 2 == 0:
    n *= 2
    a //= 2

lcm = 1
for a in A:
    if a % n != 0 or a % (2 * n) == 0:
        print(0)
        exit()
    lcm = lcm * a // gcd(lcm, a)
    if lcm // 2 > M:
        print(0)
        exit()

print((M - lcm // 2) // lcm + 1)

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