java (random number)

Generate random numbers

int a = new java.util.Random().nextInt(①);

If an integer of 1 or more is specified in ①, a random integer of 0 or more and less than the number specified in ① is assigned to a. Example: Substituting 10 causes any of 0 to 9 to be substituted for a

Command to receive one line of input from the keyboard

** Accepts character string input **

String a = new java.util.Scanner(System.in).nextLine();

** Accepts integer input **

int a = new java.util.Scanner(System.in).nextInt();

Recommended Posts

java (random number)

[Java] Random number generation method (Random)

[Java] Random method

C # (random number) memo

Random number creation (Math.random ();)

Java random, various processing

[java] Decimal number → n-ary number n-ary number → decimal number

Java

Java learning (0)

[Java] array

Java protected

[Java] Module

Java array

Studying Java ―― 9

Java scratch scratch

Java tips, tips

Java methods

Java method

java (constructor)

Java array

[Java] ArrayDeque

java (override)

java (method)

Java Day 2018

Java string

java (array)

Java static

Java serialization

java beginner 4

[Personal memo] How to interact with a random number generator in Java

JAVA paid

Studying Java ―― 4

Java (set)

java shellsort

[Java] compareTo

Studying Java -5

java reflexes

java (interface)

Java memorandum

☾ Java / Collection

Java array

Studying Java ―― 1

[Java] Array

[Java] Polymorphism

Studying Java # 0

Java review

java framework

Java features

[Java] Inheritance

FastScanner Java

Java features

java beginner 3

Java memo

java (encapsulation)

Java inheritance

[Java] Overload

Java basics

Decompile Java

[Java] Annotation

java notes