Extract only the file name excluding the directory in the directory

Postscript

The comment section is real (although it is short) Thank you @takahirom!

background

ʻOs.listdir (path)will output a list of files and directories inpath`, but if you want to get only directories or only files, it will be a little bit. I thought about it.

The environment is Python 2.7.10 and the OS is Windows 7.

The result of trying

I think there is a smarter way to do it.

import glob
import os

def fileonly_listdir(path):
    return [ i for i in os.listdir(path) if i not in [ j.replace(path, "").strip("\\") for j in glob.glob(os.path.join(path, "*") + "/")]]

Disassembled because it is difficult to understand.

import glob
import os

def fileonly_listdir(path):
    list_dir = os.listdir(path)  #Get a list of objects in a directory ... 1
    dir_only_list = glob.glob(os.path.join(path, "*") + "/")  #In a specific path, the end is"/"Object = directory only
    #However,"path\\dir\\"Will be in the form

    dir_only_list = [ i.replace(path, "").strip("\\") for i in dir_only_list ]  #Eliminate the obstacles ... 2

    file_only_list = [ i for i in list_dir if i not in dir_only_list ]  #Subtract 1 to 2

    return file_only_list

So if you want a list of directories only

import glob
[ i.replace(path, "").strip("\\") for i in glob.glob(os.path.join(path, "*") + "/")]

Is fine.

Nested list comprehensions are very difficult to understand, so it may be better to use filter.

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