[Django] Create your own 403, 404, 500 error pages

Overview

I've investigated how to create an error page such as 404 Not Found, so I'll summarize it.

The error I checked this time

I will touch on the following error codes.

• 403 Forbidden
• 404 Not Found
• 500 Internal Server Error

manner

Under any templates directory,

• 403.html
• 404.html
• 500.html

Place. Then, when the target error is thrown, the template will be read automatically.

Example

myproject
  - myapp
    - urls.py
    - views.py
    - models.py
    - app.py
    - forms.py
    - templates
      - 403.html
      - 404.html
      - 500.html

Implement your own 404 page etc. as below.

404.html

{% extends "base.html" %}
{% block content %}
<section>
    <div>
        <label>404 Not Found<br>The page you are looking for could not be found.<br><a class="hover-under" href="{% url 'top' %}">Back to top page</a></label>
    </div>
</section>
{% endblock %}

Exception that each error code is thrown out

These pages will be returned if you call an exception for which each status code should be returned.

404 Not Found Raise the Http404 class inside the django.http package.

views.py

from django.http import Http404


class MyView(View):
    def index(self):
        raise Http404

403 Forbidden There is a PermissionDenied class in django.core.exceptions.

views.py

from django.core.exceptions import PermissionDenied


class MyView(View):
    def index(self):
        if not self.request.user.is_authenticated:
            raise PermissionDenied

500 Internal Server Error Use a normal error that doesn't catch or explicitly returns something that would result in a normal InternalServerError, such as a syntax error.

views.py

from .models import Example


class MyView(View):
    def index(self):
        try:
            _instance = Example.objects.get(id=1)
        except Example.DoesNotExists:
            #Throw an exception (usually don't do much)
            raise Exception