Python has a simple HTTP server function for web development. It's convenient, but it's inconvenient because I have to put the public script directly under the directory I want to publish (I thought), and I just found out how to specify the public directory.

Conclusion

(Supports Python 3.7 and above) Below, you can enter the relative path from the script in __DIRECTORY.

Quoted from Reference 1

`server.py`


import http.server
import socketserver

PORT = 8000
DIRECTORY = "web"

class Handler(http.server.SimpleHTTPRequestHandler):
    def __init__(self, *args, **kwargs):
        super().__init__(*args, directory=DIRECTORY, **kwargs)


with socketserver.TCPServer(("", PORT), Handler) as httpd:
    print("serving at port", PORT)
    httpd.serve_forever()

Reference 1

StackOverflow "How to run a http server which serves a specific path?" I just wrote what I wanted to know.

Code meaning

If you do not specify a public directory, you can use the following code. The directory where the script exists automatically becomes the public directory. By passing a handler to TCPServer () as an argument, the appropriate argument is put in the constructor of SimpleHTTPRequestHandler in TCPServer (). So this __Handler is an image like a function pointer __. (That is, is it a "handler"?)

`Do not specify a directory.py`



Handler = http.server.SimpleHTTPRequestHandler
with socketserver.TCPServer(("", PORT), Handler) as httpd:
    print("serving at port", PORT)
    httpd.serve_forever()

So, what we are doing in the code of the above conclusion is to call the constructor of SimpleHTTPRequestHandler in TCPServer () without changing the outline (* args and ** kwargs in the code below), The __constructor is overwritten so that "arbitrary specified directory" is passed to the argument directory.

`I investigated only the difficult parts.py`



#Redefine the initialization function of SimpleHTTPRequestHandler
class Handler(http.server.SimpleHTTPRequestHandler):
    def __init__(self, *args, **kwargs):
        super().__init__(*args, directory=DIRECTORY, **kwargs)

#I really want to do this, but I get an error with insufficient arguments.
#The argument is TCP Server()I can't put it in here & I don't know because I put it properly inside.
Handler = http.server.SimpleHTTPRequestHandler(directory="web")

#This is no good either. Naturally, it is said what args are.
Handler = http.server.SimpleHTTPRequestHandler(*args,directory="web",**kwargs)